255 255 255 248
1. Subnet = 2^5= 32
2. Jumlah host = 2^y-2
= 2^3-2
= 8-2
= 6
3. Blok Subnet = 256-248
= 8
1). Blog 3 (8*2=16)
192.168.1.16
192.168.1.16---192.168.1.23
192.168.1.16-->Subnet
192.168.1.17}used Host 6
192.168.1.22}used Host 6
192.168.1.23-->Brodcast
